Given the molar mass of glucose = 342.3 g/mol, what mass of glucose is required to prepare 1 litres of 0.5M solution ? (2 marks)

To solve this problem, we need to use the formula for molarity which is:

Molarity (M) = moles of solute / volume of solution in liters

We know the molarity (0.5 M) and the volume of the solution (1 L), and we need to find the mass of glucose.

First, we need to find the moles of glucose. We can rearrange the formula to find moles:

Moles of solute = Molarity (M) * volume of solution in liters

So, moles of glucose = 0.5 M * 1 L = 0.5 moles

Next, we use the molar mass of glucose to find the mass. The molar mass of glucose is the mass of one mole of glucose, so:

Mass of glucose = moles of glucose * molar mass of glucose

Mass of glucose = 0.5 moles * 342.3 g/mol = 171.15 g

So, 171.15 g of glucose is required to prepare 1 litre of 0.5M solution.