Suppose list1 is [3, 4, 5, 20, 5, 25, 1, 3], what is list1 after list1.pop(1)?Group of answer choices
Question
Suppose list1 is [3, 4, 5, 20, 5, 25, 1, 3]
, what is list1 after list1.pop(1)
?
Group of answer choices
Solution
The pop() method in Python removes the item at the given index from the list and returns the removed item. Here, list1.pop(1) will remove the item at index 1 from list1.
Here is the step by step process:
- Identify the list: list1 is [3, 4, 5, 20, 5, 25, 1, 3]
- Identify the index to be removed: In list1.pop(1), 1 is the index to be removed. Remember that Python uses zero-based indexing, so 1 refers to the second element in the list, which is 4.
- Remove the element at the given index: After removing the element at index 1, the list becomes [3, 5, 20, 5, 25, 1, 3]
So, after list1.pop(1), list1 is [3, 5, 20, 5, 25, 1, 3].
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