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Suppose list1 is [3, 4, 5, 20, 5, 25, 1, 3], what is list1 after list1.pop(1)?Group of answer choices

Question

Suppose list1 is [3, 4, 5, 20, 5, 25, 1, 3], what is list1 after list1.pop(1)?

Group of answer choices

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Solution

The pop() method in Python removes the item at the given index from the list and returns the removed item. Here, list1.pop(1) will remove the item at index 1 from list1.

Here is the step by step process:

  1. Identify the list: list1 is [3, 4, 5, 20, 5, 25, 1, 3]
  2. Identify the index to be removed: In list1.pop(1), 1 is the index to be removed. Remember that Python uses zero-based indexing, so 1 refers to the second element in the list, which is 4.
  3. Remove the element at the given index: After removing the element at index 1, the list becomes [3, 5, 20, 5, 25, 1, 3]

So, after list1.pop(1), list1 is [3, 5, 20, 5, 25, 1, 3].

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