The third term of a geometric progression is 8, then the product of the first five terms is

Question

The third term of a geometric progression is 8, then the product of the first five terms is
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Solution 1

To find the product of the first five terms of a geometric progression, we need to determine the common ratio (r) and the first term (a).

Given that the third term is 8, we can use the formula for the nth term of a geometric progression:

an = a * r^(n-1)

Substituting n = 3 and an = 8, we have:

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