In a group of boys the number of arrangement of 4 boys is 12 times the number ofarrangements of 2 boys. The number of boys in the group is
Question
In a group of boys the number of arrangement of 4 boys is 12 times the number of arrangements of 2 boys. The number of boys in the group is
Solution
Let's assume that the number of boys in the group is "x".
To find the number of arrangements of 4 boys, we use the formula for permutations, which is nPr = n! / (n-r)!. In this case, we have 4 boys, so the number of arrangements of 4 boys is 4P4 = 4! / (4-4)! = 4! / 0! = 4! = 24.
Similarly, the number of arrangements of 2 boys is 2P2 = 2! / (2-2)! = 2! / 0! = 2! = 2.
According to the given information, the number of arrangements of 4 boys is 12 times the number of arrangements of 2 boys. So, we can set up the equation:
24 = 12 * 2
Simplifying the equation, we get:
24 = 24
This equation is true for any value of "x". Therefore, the number of boys in the group can be any number.
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