To solve this problem, we need to use the formula for power, which is P = IV, where P is power, I is current, and V is voltage. However, we don't have the voltage in this problem.

But we know that power can also be calculated by the formula P = I^2R, where R is resistance.

Given that the power P is 400 J/s (or Watts), we can rearrange the formula to solve for I (current):

I = sqrt(P/R)

Without the value of the resistance R, we cannot calculate the current I.

So, we need more information to solve this problem.

Question

To solve this problem, we need to use the formula for power, which is P = IV, where P is power, I is current, and V is voltage. However, we don't have the voltage in this problem.

But we know that power can also be calculated by the formula P = I^2R, where R is resistance.

Given that the power P is 400 J/s (or Watts), we can rearrange the formula to solve for I (current):

I = sqrt(P/R)

Without the value of the resistance R, we cannot calculate the current I.

So, we need more information to solve this problem.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for power, which is P = IV, where P is power, I is current, and V is voltage. However, we don't have the voltage in this problem.

But we know that power can also be calculated by the formula P = I^2R, where R is resistance.

Given that the power P is 400 J/s (or Watts), we can rearrange the formula to solve for I (current):

I = sqrt(P/R)

Without the value of the resistance R, we cannot calculate the current I.

So, we need more information to solve this problem.

400 J of heat is produced each second in a resistance. Find the current passing through it.

Question

400 J of heat is produced each second in a resistance. Find the current passing through it.

Solution

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