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The position of a particle moving along the x-axis is given by x = a (t – 1) + b(t – 1) where a and b are constant, then :

Question

The position of a particle moving along the x-axis is given by

x=a(t1)+b(t1) x = a (t - 1) + b (t - 1)

where a and b are constant, then:

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Solution

To analyze the sentence and the equation provided about the position of a particle along the x-axis, we can start by rewriting the expression for clarity:

  1. Understanding the Equation
    The equation is given as:
    x(t)=a(t1)+b(t1) x(t) = a(t - 1) + b(t - 1)
    This can be simplified by factoring out (t1)(t - 1):
    x(t)=(a+b)(t1) x(t) = (a + b)(t - 1)
    Here, aa and bb are constants, and x(t)x(t) represents the position of the particle at time tt.

  2. Interpreting the Result
    This position function indicates that the particle's position is linearly dependent on the time elapsed since t=1t = 1. At t=1t = 1, the position x(1)=0x(1) = 0. The rate of change of position with respect to time, or velocity, can be derived from the position function.

  3. Finding Velocity
    To find the velocity v(t)v(t), we differentiate x(t)x(t) with respect to time tt:
    v(t)=dxdt=a+b v(t) = \frac{dx}{dt} = a + b
    The velocity is constant since it does not depend on tt.

  4. Final Summary
    The motion of the particle can be described as uniform rectilinear motion since the velocity remains constant over time at a+ba + b.

Final Answer

  • The position of the particle is given by the equation x(t)=(a+b)(t1)x(t) = (a + b)(t - 1).
  • The velocity of the particle is constant at v=a+bv = a + b.

This problem has been solved

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