Calculate the amount of KMnO4 (in grams) required to prepare a 0.01 M solution in 200 mL of waterYour answer

To calculate the amount of KMnO4 required, we need to use the formula:

Molarity (M) = moles of solute / volume of solution in liters

First, we need to convert the volume from mL to L:

200 mL = 0.2 L

Next, we rearrange the formula to solve for moles of solute:

Moles of solute = Molarity (M) * volume of solution in liters

Moles of solute = 0.01 M * 0.2 L = 0.002 moles

The molar mass of KMnO4 is approximately 158.034 g/mol. We can now calculate the mass of KMnO4 required:

Mass of KMnO4 = moles of solute * molar mass of KMnO4

Mass of KMnO4 = 0.002 moles * 158.034 g/mol = 0.316 g

So, you would need approximately 0.316 grams of KMnO4 to prepare a 0.01 M solution in 200 mL of water.