1/2 * Fmax * 2 * 10^-3 + Fmax * 2.0 * 10^-3 + 1/2 * Fmax * 2 * 10^-3 = 8.0 * (0.3 + 0.3)
Question
1/2 * Fmax * 2 * 10^-3 + Fmax * 2.0 * 10^-3 + 1/2 * Fmax * 2 * 10^-3 = 8.0 * (0.3 + 0.3)
Solution
Sure, let's break down the equation step by step.
First, let's simplify the left side of the equation:
1/2 * Fmax * 2 * 10^-3 + Fmax * 2.0 * 10^-3 + 1/2 * Fmax * 2 * 10^-3
This can be simplified to:
Fmax * 10^-3 + Fmax * 2.0 * 10^-3 + Fmax * 10^-3
Which further simplifies to:
2Fmax * 10^-3 + 2Fmax * 10^-3
This simplifies to:
4Fmax * 10^-3
Now, let's simplify the right side of the equation:
8.0 * (0.3 + 0.3)
This simplifies to:
8.0 * 0.6
Which further simplifies to:
4.8
So, the equation simplifies to:
4Fmax * 10^-3 = 4.8
To solve for Fmax, we divide both sides by 4 * 10^-3:
Fmax = 4.8 / (4 * 10^-3)
This simplifies to:
Fmax = 1200 N
So, the maximum force (Fmax) is 1200 Newtons.
Similar Questions
Using the right prefixes, the quanties 3 × 10⁴ 𝘮 and 5× 10⁻⁵ 𝘴 can be expressed as; 1 point0.3 𝘮𝘮 and 0.5 µ𝘴30 𝘬𝘮 and 0.5 µ𝘴30 𝘬𝘮 and 0.5 𝘮𝘴0.3 𝘤𝘮 and 0.5 µ𝘴
Calculate the quotient below and give your answer in scientific notation. \large{\dfrac{2.40\times 10^{2}}{3.0\times 10^{-1}}} =\ ?
f log10 2 = 0.3010, the value of log10 80 is:Choices:- 1.602 1.903 3.903 None of these
If you take a BS of 6.21 at a BM with an Elev. of 94.30 and the next FS is 8.11, what is the Elev. at that point?Write your numerical answer (without units).
For the given A.P. a = 3.5, d = 0, then tn = ·············· ·(A) 0/gw 3.5(C) 103.5(D) 104.5
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.