What is the amplitude in the equation v = 35 sin(5000t)?Select one:a.5000/π Vb.5000 Vc.35 Vd.35π V

1. Break Down the Problem

In the equation $v = 35 \sin(5000t)$, we need to identify the amplitude from the sine function.

2. Relevant Concepts

The general form of a sine function is $y = A \sin(Bt + C) + D$, where:

• $A$ represents the amplitude,
• $B$ affects the frequency,
• $C$ is a phase shift, and
• $D$ is a vertical shift.

3. Analysis and Detail

In the given equation $v = 35 \sin(5000t)$, comparing it to the general form, we can specifically identify that:

• The amplitude $A = 35$.

4. Verify and Summarize

The amplitude of a sine function represents the maximum value it can reach. In this case, it is $35$ V.

Final Answer

The amplitude of the function $v = 35 \sin(5000t)$ is 35 V (option c).