What will be the output of the following Python code?def foo(x): x[0] = ['def'] x[1] = ['abc'] return id(x)q = ['abc', 'def']print(id(q) == foo(q))

The output of the given Python code will be True.

Here's the step-by-step explanation:

1. A list q is defined with two elements: 'abc' and 'def'.
2. The id() function in Python returns the “identity” of an object, which is unique and constant for this object during its lifetime.
3. The function foo(x) is defined, which takes a list as an argument. Inside this function, the first and second elements of the list are modified to ['def'] and ['abc'] respectively. Then, the function returns the id of the modified list.
4. When calling foo(q), the list q is passed to the function. The function modifies q and returns its id.
5. The print() function compares the id of q before and after the call to foo(). Since lists are mutable in Python, the function foo() modifies the list in-place, without creating a new list. Therefore, the id of the list remains the same, and the comparison id(q) == foo(q) returns True.
6. So, True is printed as the output of this Python code.