The specific growth rate of a yeast having a doubling time of 0.693 h (roundedoff to nearest integer) is___________h-1

1. Break Down the Problem

To find the specific growth rate (μ) of the yeast from the doubling time, we need to use the relationship between doubling time (td) and specific growth rate.

2. Relevant Concepts

The specific growth rate can be related to the doubling time using the following formula: $\mu = \frac{\ln(2)}{t_d}$ where:

• $\mu$ = specific growth rate (h$^{-1}$)
• $t_d$ = doubling time (h)
• $\ln(2) \approx 0.693$

3. Analysis and Detail

Given that the doubling time $t_d = 0.693$ h, we will substitute this value into our formula: $\mu = \frac{\ln(2)}{0.693}$

Calculate $\ln(2)$ as approximately 0.693: $\mu = \frac{0.693}{0.693} = 1$

4. Verify and Summarize

The calculations seem correct and the specific growth rate of the yeast, rounded to the nearest integer, is: $\mu = 1 \text{ h}^{-1}$

Final Answer

The specific growth rate of the yeast is 1 h$^{-1}$.