For the parabola y2 = 16x, length of a focal chord, whose one end point is (16,16), is L2, then the value of L is
Question
For the parabola y^2 = 16x
, the length of a focal chord, whose one end point is (16, 16)
, is L2
, then the value of L
is
Solution
To find the length of the focal chord, we need to determine the coordinates of its other endpoint.
Given that one endpoint is (16, 16), we can substitute these values into the equation of the parabola y^2 = 16x to find the corresponding x-coordinate.
Plugging in y = 16, we get:
(16)^2 = 16x 256 = 16x x = 16
So, the other endpoint of the focal chord is (x, y) = (16, 16).
Now, we can calculate the length of the focal chord using the distance formula.
The distance between two points (x1, y1) and (x2, y2) is given by:
L = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates of the two endpoints, we have:
L = sqrt((16 - 16)^2 + (16 - 16)^2) L = sqrt(0 + 0) L = sqrt(0) L = 0
Therefore, the length of the focal chord, L, is 0.
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