A gas at a volume of 4 liters is at a pressure of 2 atm. The volume is changed to 16 Liters, what must the new pressure be?
Question
A gas at a volume of 4 liters is at a pressure of 2 atm. The volume is changed to 16 Liters, what must the new pressure be?
Solution
This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In other words, P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Here's how to solve it:
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Identify the initial pressure (P1) and volume (V1). In this case, P1 is 2 atm and V1 is 4 liters.
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Identify the final volume (V2). In this case, V2 is 16 liters.
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Substitute these values into Boyle's Law (P1V1 = P2V2) and solve for P2 (the final pressure).
So, 2 atm * 4 L = P2 * 16 L.
Solving for P2 gives P2 = (2 atm * 4 L) / 16 L = 0.5 atm.
So, the new pressure must be 0.5 atm.
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