29. A gas tank holds 2,785 L of propane at 830 mmHg. What is the volume of the propane at standard pressure (760 mmHg)?

Sure, to solve this problem, we can use the gas law formula which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume. This is represented as P1V1 = P2V2.

Here's the step-by-step solution:

1. Identify the given values: Initial Pressure, P1 = 830 mmHg Initial Volume, V1 = 2,785 L Final Pressure, P2 = 760 mmHg We need to find the final volume, V2.

2. Substitute the given values into the formula: (830 mmHg * 2,785 L) = (760 mmHg * V2)

3. Solve for V2: V2 = (830 mmHg * 2,785 L) / 760 mmHg

4. Calculate the value of V2 to get the final volume of the propane at standard pressure.