What are the largest 4-digit and the smallest 3-digit numbers divisible by 6, 15, 21 and 24? Question Description : 9999,9999240,840 9980,840 9235,420

To find the largest 4-digit number divisible by 6, 15, 21, and 24, we need to find the least common multiple (LCM) of these numbers. The LCM of 6, 15, 21, and 24 is 840.

Now, we need to find the largest 4-digit number that is divisible by 840. To do this, we divide the largest 4-digit number, 9999, by 840. The quotient is 11 and the remainder is 939. So, we subtract the remainder from 9999 to get the largest 4-digit number divisible by 840, which is 9060.

To find the smallest 3-digit number divisible by 6, 15, 21, and 24, we start from the smallest 3-digit number, 100, and keep adding the LCM (840) until we get a 3-digit number. The smallest 3-digit number divisible by 840 is 840 itself.

So, the largest 4-digit number divisible by 6, 15, 21, and 24 is 9060 and the smallest 3-digit number divisible by these numbers is 840.