Knowee
Questions
Features
Study Tools

What are the largest 4-digit and the smallest 3-digit numbers divisible by 6, 15, 21 and 24? Question Description : 9999,9999240,840 9980,840 9235,420

Question

What are the largest 4-digit and the smallest 3-digit numbers divisible by 6, 15, 21 and 24?

Question Description:
9999, 9999240, 840
9980, 840
9235, 420

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the largest 4-digit number divisible by 6, 15, 21, and 24, we need to find the least common multiple (LCM) of these numbers. The LCM of 6, 15, 21, and 24 is 840.

Now, we need to find the largest 4-digit number that is divisible by 840. To do this, we divide the largest 4-digit number, 9999, by 840. The quotient is 11 and the remainder is 939. So, we subtract the remainder from 9999 to get the largest 4-digit number divisible by 840, which is 9060.

To find the smallest 3-digit number divisible by 6, 15, 21, and 24, we start from the smallest 3-digit number, 100, and keep adding the LCM (840) until we get a 3-digit number. The smallest 3-digit number divisible by 840 is 840 itself.

So, the largest 4-digit number divisible by 6, 15, 21, and 24 is 9060 and the smallest 3-digit number divisible by these numbers is 840.

This problem has been solved

Similar Questions

The largest four digit number exactly divisible by each of 12, 15, 18 and 27 is:a.9720b.9930c.9960d.9690

What is the largest six-digit number that is divisible by 8, 12, 16, 24, and 32?

Find the largest number of four digits which is exactly divisible by 88 ?9955994499889966

Find the greatest five-digit number which is divisible by 7, 10, 15, 21 and 28.Choices:- 99540 99988 99960 99990Save AnswerSkip this questionFinish Exam

The greatest four digit number which is divisible by 18, 25, 30, and 48 is:Options :A] 9000B] 9200C] 7200D] 9729

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.