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Use the quotient rule to find the derivative of the following function.𝑓(𝑥)=cos(𝑥)ln(𝑥)𝑓′(𝑥)=

Question

Use the quotient rule to find the derivative of the following function.

Let 𝑓(𝑥) = cos(𝑥)ln(𝑥)

Then, 𝑓′(𝑥) =

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Solution

To find the derivative of the function f(x)=cos(x)ln(x) f(x) = \cos(x) \ln(x) using the product rule, we break down the problem as follows:

1. Break Down the Problem

Identify the two functions involved:

  • u=cos(x) u = \cos(x)
  • v=ln(x) v = \ln(x)

2. Relevant Concepts

The product rule states that the derivative of a product of two functions is given by: (fg)=fg+fg (fg)' = f'g + fg' Thus, we need to find u u' and v v' .

3. Analysis and Detail

  1. Compute u u' :

    • u=cos(x) u = \cos(x)
    • Therefore, u=sin(x) u' = -\sin(x)
  2. Compute v v' :

    • v=ln(x) v = \ln(x)
    • Thus, v=1x v' = \frac{1}{x}
  3. Apply the product rule: f(x)=uv+uv=(sin(x))ln(x)+cos(x)(1x) f'(x) = u'v + uv' = (-\sin(x)) \ln(x) + \cos(x) \left(\frac{1}{x}\right)

4. Verify and Summarize

Combining the two terms gives us the final expression for the derivative: f(x)=sin(x)ln(x)+cos(x)x f'(x) = -\sin(x) \ln(x) + \frac{\cos(x)}{x}

Final Answer

f(x)=sin(x)ln(x)+cos(x)x f'(x) = -\sin(x) \ln(x) + \frac{\cos(x)}{x}

This problem has been solved

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