The equation of a circle in a coordinate plane is given by the formula:

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is at (1,2) and the radius is 4, we can substitute these values into the formula to get the equation of the circle:

(x - 1)² + (y - 2)² = 4²

Simplifying the right side of the equation gives:

(x - 1)² + (y - 2)² = 16

So, the equation of the circle with its center at (1,2) and a radius of 4 is (x - 1)² + (y - 2)² = 16.

Question

The equation of a circle in a coordinate plane is given by the formula:

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is at (1,2) and the radius is 4, we can substitute these values into the formula to get the equation of the circle:

(x - 1)² + (y - 2)² = 4²

Simplifying the right side of the equation gives:

(x - 1)² + (y - 2)² = 16

So, the equation of the circle with its center at (1,2) and a radius of 4 is (x - 1)² + (y - 2)² = 16.

Knowee AI · Accepted Answer

The equation of a circle in a coordinate plane is given by the formula:

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is at (1,2) and the radius is 4, we can substitute these values into the formula to get the equation of the circle:

(x - 1)² + (y - 2)² = 4²

Simplifying the right side of the equation gives:

(x - 1)² + (y - 2)² = 16

So, the equation of the circle with its center at (1,2) and a radius of 4 is (x - 1)² + (y - 2)² = 16.

If there is a circle with its center at (1,2) and a radius of 4. Find the equation of this c

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