What will the value of $x be at the end of this script?<?PHP$x=0;$x=$x+1;echo $x.” value”;$x++;?>

Question

What will the value of $x be at the end of this script?

$x=0;
$x=$x+1;
echo $x.” value”;
$x++;

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Solution

At the end of this script, the value of $x will be 2.

Here is the step-by-step explanation:

Initially, $x is assigned the value of 0:$ x = 0.
The next line increments the value of $x by 1:$ x = $x + 1. Now,$ x is 1.
The echo statement outputs the value of $x followed by the string " value": echo$ x . " value". This will display "1 value".
Finally, the $x++ statement increments the value of$ x by 1 again. Now, $x becomes 2.

Therefore, the final value of $x is 2.

This problem has been solved

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