A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
Question
A stone is released from the top of a tower of height 19.6 m.
Calculate its final velocity just before touching the ground.
Solution
Sure, we can solve this problem using the physics equation for motion:
v² = u² + 2gs
where: v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and s is the distance.
Given: u = 0 (since the stone is released from rest), g = 9.8 m/s² (approximate value of gravity on Earth), and s = 19.6 m (height of the tower).
Substituting these values into the equation, we get:
v² = 0 + 29.819.6 v² = 384.16
Taking the square root of both sides to solve for v, we get:
v = sqrt(384.16) v = 19.6 m/s
So, the final velocity of the stone just before touching the ground is 19.6 m/s.
Similar Questions
A stone is released from the top of a tower of height 980 m. Calculate its velocity after 3 seconds. (Take g = 9.8 m/s2)
A stone is projected horizontally with a velocity of 10m/s from the top of a building 39.2 m high. How long will the stone take to hit the ground.
If a stone is horizontally launched at a certain height, what will be the vertical velocity as it reaches the ground?
A stone is dropped from the top of a tower travels 25m in the last second of itsmotion. If 210 /g m s height of the tower isA) 54m B) 45m C) 25m D) 64m
A body is dropped from a tower with zero velocity reaches the ground in 10s. The height of the tower is about :(given : g = 10 m/s2)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.