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Find the values of $x$x​ and $y$y​ that satisfy the equation.$-10x+12i=20+3yi$−10x+12i=20+3yi​$x=$x=​   and  $y=$y=​

Question

Find the values of xx and yy that satisfy the equation.

-10x + 12i = 20 + 3yi

  • x=x =
  • y=y =
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Solution

To solve for xx and yy, we can equate the real and imaginary parts of the complex numbers on both sides of the equation.

The equation given is 10x+12i=20+3yi-10x + 12i = 20 + 3yi.

Equating the real parts, we get: 10x=20-10x = 20. Solving for xx, we get x=2x = -2.

Equating the imaginary parts, we get: 12=3y12 = 3y. Solving for yy, we get y=4y = 4.

So, the solution to the equation is x=2x = -2 and y=4y = 4.

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