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Find the points of intersection of the graphs of the equations. (Enter (0, 0) for the pole.)r = 8 + 8 cos(๐œƒ)r = 8 โˆ’ 8 sin(๐œƒ)r โ‰ฅ 0, 0 โ‰ค ๐œƒ < 2๐œ‹

Question

Find the points of intersection of the graphs of the equations.

(Enter (0, 0) for the pole.)
r=8+8cosโก(ฮธ) r = 8 + 8 \cos(\theta)
r=8โˆ’8sinโก(ฮธ) r = 8 - 8 \sin(\theta)
rโ‰ฅ0,โ€…โ€Š0โ‰คฮธ<2ฯ€ r \geq 0, \; 0 \leq \theta < 2\pi

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Solution

To find the points of intersection of the two polar equations, we need to set them equal to each other and solve for ๐œƒ.

So, we have:

8 + 8 cos(๐œƒ) = 8 - 8 sin(๐œƒ)

Rearranging the equation gives:

8 cos(๐œƒ) + 8 sin(๐œƒ) = 0

Dividing by 8:

cos(๐œƒ) + sin(๐œƒ) = 0

This equation is satisfied when ๐œƒ = 3๐œ‹/4 and ๐œƒ = 7๐œ‹/4.

Substituting ๐œƒ = 3๐œ‹/4 into the first equation gives:

r = 8 + 8 cos(3๐œ‹/4) = 8 - 8 sqrt(2)/2 = 8 - 4 sqrt(2)

Substituting ๐œƒ = 7๐œ‹/4 into the first equation gives:

r = 8 + 8 cos(7๐œ‹/4) = 8 + 8 sqrt(2)/2 = 8 + 4 sqrt(2)

So, the points of intersection are (8 - 4 sqrt(2), 3๐œ‹/4) and (8 + 4 sqrt(2), 7๐œ‹/4).

This problem has been solved

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