# Write an equation of the plane with normal vector n =⟨−7,−4,−6⟩ passing through the point (−8,4,6) in scalar form answer box =20

## Question

## Solution 1

The equation of a plane in 3D space is given by the formula:

A(x - x0) + B(y - y0) + C(z - z0) = 0

where (A, B, C) is the normal vector of the plane, and (x0, y0, z0) is a point on the plane.

In this case, the normal vector n =⟨−7,−4,−6⟩, and the point is (−8,4,6). So, A = -7, B = -4, C = -6, x0 Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

```
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI
```

## Similar Questions

Write an equation of the plane with normal vector n =⟨−7,−4,−6⟩ passing through the point (−8,4,6) in scalar form answer box =20

Write an equation of the plane with normal vector n =⟨−7,−4,−6⟩ passing through the point (−8,4,6) in scalar form in the form of equation = 20

(1 point) The general (Cartesian) form for the plane passing through the point [math] and perpendicular to the line [math] with vector form [math] is .

The plane passing through the origin and containing the lines whose direction cosines are proportional to 1,-2,2 and 2,3,-1 passes through the point

Find the equation of the tangent plane and normal line at the point (1,2, −1) tothe surface 𝑥2 + 2𝑦2 + 3𝑧2 = 12

## Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.