A man heterozygous for blood group B marries a woman having blood group O, then the percentage of progeny having blood group A would be75%50%25%Nil
Question
A man heterozygous for blood group B marries a woman having blood group O, then the percentage of progeny having blood group A would be
- 75%
- 50%
- 25%
- Nil
Solution
The percentage of progeny having blood group A would be Nil.
Here's why:
A man heterozygous for blood group B means he has one allele for blood group B (I^B) and one allele for blood group O (i). His genotype is I^Bi.
A woman with blood group O has two alleles for blood group O (i). Her genotype is ii.
When they have a child, the child gets one allele from each parent. The possible combinations are I^Bi (which results in blood group B) and ii (which results in blood group O).
There is no possibility for the child to have blood group A because neither parent has an allele for blood group A (I^A). Therefore, the percentage of progeny having blood group A is 0%, or Nil.
Similar Questions
If a man who has heterozygous type A blood and a woman with type AB blood have offspring, what are the chances that they will have a baby with type O blood?
If both parents are heterozygous for sickle-cell anemia ( HbA HbS ), what percentage of their offspring will have a homozygous genotype?A. 25B. 50C. 75D. 0
What could be the possible genotypes in context to blood group if the man and woman have a girl child? IBIo, IBIB IBIo, IoIo Only IBIB Only IoIo
f the blood groups of mother and father are AB and O, respectively, what are the blood groupspossible for their child
Both parents have AB blood. What is the probability they will have a child that has type A blood? Group of answer choices75%100%25%0%50%
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.