A 0.52 kilogram rocket is launched by an engine that exerts an average force of 8.00 N. What is the rocket's acceleration in m/s2 correct to one decimal place
Question
A 0.52 kilogram rocket is launched by an engine that exerts an average force of 8.00 N.
What is the rocket's acceleration in m/s² correct to one decimal place?
Solution
To find the acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. The formula is:
a = F/m
where: a is the acceleration, F is the force, and m is the mass.
Given in the problem: F = 8.00 N (Newtons) and m = 0.52 kg (kilograms)
Substituting these values into the formula, we get:
a = 8.00 N / 0.52 kg = 15.38 m/s²
Rounding to one decimal place, the rocket's acceleration is 15.4 m/s².
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