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In a full binary tree if number of internal nodes is I, then number of nodes N are? a) N = 2l b) N = I + 1 c) N = I – 1 d) N = 2l + 1

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Solution

In a full binary tree, the number of nodes (N) is related to the number of internal nodes (I) by the formula N = 2I + 1. So, the correct answer is d) N = 2I + 1.

Here's why:

In a full binary tree, each internal node has exactly two children. Therefore, the total number of nodes is the sum of the internal nodes and their children. Since each internal node contributes two children, the total number of nodes is 2I (two times the number of internal nodes) plus the root node, which gives us N = 2I + 1.

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