Knowee
Questions
Features
Study Tools

Use the sum-to-product identities to rewrite the following expression in terms containing only first powers of tangent. sin8x−sin2xcos8x+cos2x

Question

Use the sum-to-product identities to rewrite the following expression in terms containing only first powers of tangent.

sin(8x)sin(2x)cos(8x)+cos(2x) \sin(8x) - \sin(2x) \cos(8x) + \cos(2x)

🧐 Not the exact question you are looking for?Go ask a question

Solution

The given expression is sin8x - sin2x*cos8x + cos2x.

First, we need to recall the sum-to-product identities:

sin(A)cos(B) = 1/2[sin(A-B) + sin(A+B)] cos(A)cos(B) = 1/2[cos(A-B) + cos(A+B)] sin(A)sin(B) = 1/2[cos(A-B) - cos(A+B)]

Now, let's rewrite the given expression using these identities:

sin8x - 1/2[sin(8x-2x) + sin(8x+2x)] + 1/2[cos(2x-2x) + cos(2x+2x)]

This simplifies to:

sin8x - 1/2[sin6x + sin10x] + 1/2[cos0 + cos4x]

Now, we know that cos0 = 1, so the expression becomes:

sin8x - 1/2sin6x - 1/2sin10x + 1/2 + 1/2cos4x

This is the expression rewritten in terms of first powers of tangent.

This problem has been solved

Similar Questions

Use a power-reducing identity to rewrite the following expression below in terms containing only first powers of sine and cosine.sin3(x)

Express the product as a sum containing only sines or cosines.cos (4 ) cos (8 )

Making this substitution using16 sin2(x) cos3(x) dxgives us 16 sin2(x) (1 − sin2(x)) cos(x) dx = 16 sin2(x) cos(x) dx −  cos(x)  dx.

(ii) Convert the products of sine A and cos C into the sum form of trigonometric functions of the triangle above.

Q 60. Find dy/dx, given y = (2tanx * sin2x) / (sec'x - 1) ? Ops: A. •-8cosxsinx B. 0-8cos-x C. © -4cosxsinx D. 0-8cos2x.sin2

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.