R1 = 0b1111, R2 = 0b0101 BIC R0, R1, R2  *1 pointR0 = 0b1010R0 = 0b1111R0 = 0b0101R0 = 0b1100

Question

R1 = 0b1111, R2 = 0b0101 BIC R0, R1, R2  *1 pointR0 = 0b1010R0 = 0b1111R0 = 0b0101R0 = 0b1100
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Solution 1

The BIC (Bitwise Clear) operation in assembly language clears the bits in the destination register (R0) that are set in the second source register (R2), while leaving other bits unchanged. The operation can be represented as R0 = R1 & ~R2.

Here, R1 = 0b1111 and R2 = 0b0101.

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