R1 = 0b1111, R2 = 0b0101 BIC R0, R1, R2 *1 pointR0 = 0b1010R0 = 0b1111R0 = 0b0101R0 = 0b1100

Question

R1 = 0b1111, R2 = 0b0101

BIC R0, R1, R2
*1 point

R0 = 0b1010
R0 = 0b1111
R0 = 0b0101
R0 = 0b1100

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Solution

The BIC (Bitwise Clear) operation in assembly language clears the bits in the destination register (R0) that are set in the second source register (R2), while leaving other bits unchanged. The operation can be represented as R0 = R1 & ~R2.

Here, R1 = 0b1111 and R2 = 0b0101.

First, we need to find the bitwise NOT of R2, which is ~R2.

R2 = 0b0101 ~R2 = 0b1010

Then, we perform the bitwise AND operation on R1 and ~R2.

R1 = 0b1111 ~R2 = 0b1010 R0 = R1 & ~R2 = 0b1010

So, R0 = 0b1010.

This problem has been solved

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