In which block does an element with the electron configuration [Xe] 6s24f145d106p1 belong?Group of answer choicesf blocks blockp blockd block

1. Break Down the Problem

To determine the block an element belongs to based on its electron configuration, we need to analyze the highest energy level and the type of orbital that has the last electron.

2. Relevant Concepts

• The electron configuration given is $[Xe] 6s^2 4f^{14} 5d^{10} 6p^1$.
• Here, the highest principal quantum number is 6, and the last occupied orbital is a p orbital ($6p^1$).

3. Analysis and Detail

• The term "block" in the context of the periodic table refers to the type of atomic orbital that is being filled with electrons:
  • s block: The last electron enters an s orbital.
  • p block: The last electron enters a p orbital.
  • d block: The last electron enters a d orbital.
  • f block: The last electron enters an f orbital.
• In this case, the last electron is in the $p$ orbital ($6p^1$), which indicates that the element is part of the p block of the periodic table.

4. Verify and Summarize

Since the last electron is in a p orbital, we can confidently classify this element as belonging to the p block. No further calculations are necessary.

Final Answer

The element with the electron configuration $[Xe] 6s^2 4f^{14} 5d^{10} 6p^1$ belongs to the p block.