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The function f is defined by f  x   = 3x + k, where k is a constant. Find the value of k if the graph of f passes through the point (−1, 8).

Question

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Solution

1. Break Down the Problem

We need to find the value of the constant k k in the function f(x)=3x+k f(x) = 3x + k , given that the graph passes through the point (1,8)(-1, 8). This means that when x=1 x = -1 , f(x)=8 f(x) = 8 .

2. Relevant Concepts

To solve for k k , we will substitute the coordinates of the point into the function and set it equal to 8: f(1)=3(1)+k=8 f(-1) = 3(-1) + k = 8

3. Analysis and Detail

Now, we will calculate:

f(1)=3(1)+k f(-1) = 3(-1) + k =3+k = -3 + k Setting this equal to 8, we have: 3+k=8 -3 + k = 8

Now, solve for k k : k=8+3 k = 8 + 3 k=11 k = 11

4. Verify and Summarize

We can verify by plugging k=11 k = 11 back into the function and checking if the point (-1, 8) is on the graph. f(1)=3(1)+11=3+11=8 f(-1) = 3(-1) + 11 = -3 + 11 = 8 This confirms that our calculations and logic are correct.

Final Answer

The value of k k is 11 11 .

This problem has been solved

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