One million is to be divided among the 3 children of a widower in the ratio of 10:12:18. By how much is the largest share greater than the smallest share?
Question
One million is to be divided among the 3 children of a widower in the ratio of 10:12:18.
By how much is the largest share greater than the smallest share?
Solution
The first step is to add up the parts of the ratio, which are 10, 12, and 18. This gives us a total of 40 parts.
Next, we need to determine the value of each part. We do this by dividing the total amount of money, which is one million, by the total number of parts, which is 40. So, 1,000,000 ÷ 40 = 25,000. This means each part is worth 25,000.
The smallest share is for the child with the ratio of 10, so their share is 10 parts x 25,000 = 250,000.
The largest share is for the child with the ratio of 18, so their share is 18 parts x 25,000 = 450,000.
To find out by how much the largest share is greater than the smallest share, we subtract the smallest share from the largest share. So, 450,000 - 250,000 = 200,000.
Therefore, the largest share is greater than the smallest share by 200,000.
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