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What correction should be made to the following code to calculate the Fibonacci number correctly?def fib(n): return fib(n-1) + fib(n-2)

Question

What correction should be made to the following code to calculate the Fibonacci number correctly?

def fib(n):
    return fib(n-1) + fib(n-2)
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Solution

The code provided is a recursive function to calculate the Fibonacci number, but it lacks a base case. Without a base case, the function will keep calling itself indefinitely, leading to a stack overflow error.

Here's the corrected code:

def fib(n):
    if n <= 0:
        return "Input should be a positive integer."
    elif n == 1:
        return 0
    elif n == 2:
        return 1
    else:
        return fib(n-1) + fib(n-2)

In this corrected code, we have added base cases for n == 1 and n == 2. When n == 1, the function returns 0 and when n == 2, it returns 1. These are the first two numbers in the Fibonacci sequence.

We also added a condition to check if n is less than or equal to 0. If it is, the function returns an error message. This is because the Fibonacci sequence is not defined for non-positive integers.

This problem has been solved

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