What correction should be made to the following code to calculate the Fibonacci number correctly?def fib(n): return fib(n-1) + fib(n-2)
Question
What correction should be made to the following code to calculate the Fibonacci number correctly?
def fib(n):
return fib(n-1) + fib(n-2)
Solution
The code provided is a recursive function to calculate the Fibonacci number, but it lacks a base case. Without a base case, the function will keep calling itself indefinitely, leading to a stack overflow error.
Here's the corrected code:
def fib(n):
if n <= 0:
return "Input should be a positive integer."
elif n == 1:
return 0
elif n == 2:
return 1
else:
return fib(n-1) + fib(n-2)
In this corrected code, we have added base cases for n == 1
and n == 2
. When n == 1
, the function returns 0
and when n == 2
, it returns 1
. These are the first two numbers in the Fibonacci sequence.
We also added a condition to check if n
is less than or equal to 0
. If it is, the function returns an error message. This is because the Fibonacci sequence is not defined for non-positive integers.
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