The first of two numbers is three less than the second number. Two times the second number plus three times the first is 21. What are the two numbers?

Question

Two times the second number plus three times the first is 21. What are the two numbers?

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Let's denote the first number as x and the second number as y.

From the problem, we have two equations:

x = y - 3 (since the first number is three less than the second number)
2y + 3x = 21 (since two times the second number plus three times the first is 21)

We can substitute equation 1) into equation 2) to solve for y:

2y + 3(y - 3) = 21 2y + 3y - 9 = 21 5y = 30 y = 6

Substitute y = 6 into equation 1) to solve for x:

x = 6 - 3 x = 3

So, the two numbers are 3 and 6.

This problem has been solved

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