Two identical heaters 240 V, 1000 W are connected in series across a supply of 240 V line, then the combined power is:

To solve this problem, we need to understand a few basic concepts about electricity:

1. Power (P) is given by the formula P = V^2 / R, where V is voltage and R is resistance.
2. When two identical resistors (in this case, the heaters) are connected in series, their total resistance is the sum of their individual resistances.

Given that each heater operates at 240 V and 1000 W, we can first find the resistance of one heater:

R = V^2 / P = (240 V)^2 / 1000 W = 57.6 ohms

Since the two heaters are connected in series, their total resistance is:

R_total = R1 + R2 = 57.6 ohms + 57.6 ohms = 115.2 ohms

Now, we can find the total power when the two heaters are connected in series to a 240 V supply:

P_total = V^2 / R_total = (240 V)^2 / 115.2 ohms = 500 W

So, the combined power of the two heaters connected in series across a 240 V supply is 500 W.