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A tree casts a shadow 24ft long from its base with an angle of elevation of the sun of 40° How tall is the tree?*15.43 ft12 ft12.34 ft20.14 ft

Question

A tree casts a shadow 24ft long from its base with an angle of elevation of the sun of 40° How tall is the tree?

  • 15.43 ft
  • 12 ft
  • 12.34 ft
  • 20.14 ft
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Solution

To solve this problem, we can use the tangent of the angle of elevation, which is the ratio of the opposite side (the height of the tree) to the adjacent side (the length of the shadow).

The formula is: tan(θ) = opposite/adjacent

Here, the angle of elevation (θ) is 40° and the length of the shadow (adjacent) is 24ft. We need to find the height of the tree (opposite).

Rearranging the formula to find the opposite side gives us: opposite = tan(θ) * adjacent

Substituting the given values into the formula gives us: height of the tree = tan(40°) * 24ft

Using a calculator to find the tangent of 40 degrees and multiplying by 24 gives us the height of the tree.

So, the correct answer is the result of this calculation.

This problem has been solved

Similar Questions

The angle of elevation of the sun, when the length of the shadow of a tree sqrt(3) times the height of the tree, is:

Find the angle of elevation of the sun if a building 78 meters high, cast a shadow of 45 meters.*29.98°60.18°

The shadow of a tower standing on a level ground is found to be 40 m longer when Suns altitude is 30 than when it was 60. Find the height of the tower.

The angle of elevation of the sun is 35 degrees at the time a pole casts a shadow of 150 m long. Find the height of the pole.

A 10- meter vertical wall cast a shadow 10√3 meters. What is the angle of elevation of the sun from the ground?

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