If maximum velocity with which an electron can be emitted from a photo cell is 4 × 108 cm/s, the stopping potential is (mass of electron = 9 × 10–31 kg)
Question
Solution 1
To find the stopping potential, we can use the equation:
eV = 1/2 mv^2
where e is the charge of an electron (1.6 × 10^-19 C), V is the stopping potential, m is the mass of the electron (9 × 10^-31 kg), and v is the maximum velocity of the electron (4 × 10^8 cm/s).
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