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A block slides down an incline of an angle of 30° with an acceleration of g/4. Find the kinetic friction coefficient.

Question

A block slides down an incline of an angle of 30° with an acceleration of g4 \frac{g}{4} . Find the kinetic friction coefficient.

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Solution

Sure, let's solve this step by step.

  1. First, we need to understand the forces acting on the block. There are three main forces: the weight of the block (mg), the normal force (N), and the friction force (f).

  2. The weight of the block can be decomposed into two components: one perpendicular to the incline (mg cos θ) and one parallel to the incline (mg sin θ). Here, θ is the angle of the incline, which is 30°.

  3. The normal force is equal to the component of the weight perpendicular to the incline, so N = mg cos θ.

  4. The friction force can be calculated using the formula f = μN, where μ is the coefficient of kinetic friction that we want to find.

  5. According to Newton's second law, the net force acting on the block is equal to its mass times its acceleration. The net force is the component of the weight parallel to the incline minus the friction force, so mg sin θ - f = ma.

  6. We know that the acceleration of the block is g/4, so we can substitute this into the equation: mg sin θ - f = mg/4.

  7. Substituting the expression for the friction force (f = μN) into the equation, we get mg sin θ - μN = mg/4.

  8. Substituting the expression for the normal force (N = mg cos θ) into the equation, we get mg sin θ - μmg cos θ = mg/4.

  9. We can cancel out the mass (m) from all terms, and we get g sin θ - μg cos θ = g/4.

  10. Solving this equation for μ, we get μ = (g sin θ - g/4) / (g cos θ).

  11. Substituting the given values (g = 9.8 m/s², θ = 30°), we get μ = (9.8 sin 30 - 9.8/4) / (9.8 cos 30).

  12. Calculating this, we get μ ≈ 0.224.

So, the coefficient of kinetic friction is approximately 0.224.

This problem has been solved

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