5. Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each colour.
Question
5. Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls, and 5 blue balls if each selection consists of 3 balls of each colour.
Solution
To solve this problem, we need to use the combination formula which is C(n, r) = n! / [(r!(n-r)!)] where n is the total number of items, and r is the number of items to choose.
Step 1: Calculate the number of ways to select 3 balls from 6 red balls. This can be done using the combination formula C(6, 3) = 6! / [(3!(6-3)!)] = 20.
Step 2: Calculate the number of ways to select 3 balls from 5 white balls. This can be done using the combination formula C(5, 3) = 5! / [(3!(5-3)!)] = 10.
Step 3: Calculate the number of ways to select 3 balls from 5 blue balls. This can be done using the combination formula C(5, 3) = 5! / [(3!(5-3)!)] = 10.
Step 4: Since each selection consists of 3 balls of each colour, we multiply the results from steps 1, 2, and 3. So, the total number of ways to select 9 balls from 6 red balls, 5 white balls, and 5 blue balls is 20 * 10 * 10 = 2000.
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