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The first five terms of a number sequence are shown below.10,14,18,22,26Find an expression for the (𝑛+1)th term, in terms of 𝑛.

Question

The first five terms of a number sequence are shown below.

10, 14, 18, 22, 26

Find an expression for the (𝑛+1)th term, in terms of 𝑛.

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Solution

1. Break Down the Problem

We need to identify the pattern in the given sequence and find a general expression for the (n+1) (n+1) -th term of the sequence.

2. Relevant Concepts

The given sequence is: 10,14,18,22,26 10, 14, 18, 22, 26

We observe the differences between each term:

  • 1410=4 14 - 10 = 4
  • 1814=4 18 - 14 = 4
  • 2218=4 22 - 18 = 4
  • 2622=4 26 - 22 = 4

This shows that the sequence increases by a constant value of 4, indicating it is an arithmetic sequence.

3. Analysis and Detail

The first term a1 a_1 is 10, and the common difference d d is 4. The general expression for the n n -th term of an arithmetic sequence is given by: an=a1+(n1)d a_n = a_1 + (n-1)d

Plugging in the values: an=10+(n1)4 a_n = 10 + (n-1) \cdot 4 Simplifying this expression: an=10+4n4 a_n = 10 + 4n - 4 an=4n+6 a_n = 4n + 6

To find the (n+1) (n+1) -th term, we simply plug in n+1 n+1 : an+1=4(n+1)+6 a_{n+1} = 4(n+1) + 6 an+1=4n+4+6 a_{n+1} = 4n + 4 + 6 an+1=4n+10 a_{n+1} = 4n + 10

4. Verify and Summarize

We confirm that this expression produces the correct terms for the sequence. For n=1 n = 1 , a2=41+10=14 a_{2} = 4 \cdot 1 + 10 = 14 ; for n=2 n = 2 , a3=42+10=18 a_{3} = 4 \cdot 2 + 10 = 18 , and so forth.

Final Answer

The expression for the (n+1) (n+1) -th term in terms of n n is: an+1=4n+10 a_{n+1} = 4n + 10

This problem has been solved

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