While going 45th of speed a man reaches 25 min late what was the initial time taken by man to travel?Options140 min100 min120 min150 min

The problem can be solved using the concept of relative speed.

Step 1: Let's denote the initial speed as 's' and the initial time as 't'.

Step 2: According to the problem, the man is now going at 4/5th of his initial speed. This means his speed is now 4s/5.

Step 3: As we know, speed = distance/time. If the distance remains the same, then the time is inversely proportional to the speed. So, if the speed is 4s/5, the time taken would be 5t/4.

Step 4: The problem states that this new time is the initial time 't' plus an extra 25 minutes. So, we can write the equation 5t/4 = t + 25.

Step 5: Solving this equation for 't' gives t = 100 minutes.

So, the initial time taken by the man to travel was 100 minutes.