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At 30°C, weight of a saturated solution is 20g. If it contains 5g of solute, its solubility will be

Question

At 30°C, weight of a saturated solution is 20g. If it contains 5g of solute, its solubility will be

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Solution

1. Break Down the Problem

We need to find the solubility of the solute in the given saturated solution. Solubility is typically expressed as the maximum amount of solute that can dissolve in a specific amount of solvent at a certain temperature.

2. Relevant Concepts

The solubility (S) can be calculated using the formula: S=mass of solutemass of saturated solution×100 S = \frac{\text{mass of solute}}{\text{mass of saturated solution}} \times 100 where:

  • Mass of solute = 5 g
  • Mass of saturated solution = 20 g

3. Analysis and Detail

Substituting the values into the solubility formula: S=5g20g×100 S = \frac{5 \, \text{g}}{20 \, \text{g}} \times 100

4. Verify and Summarize

Now we calculate: S=520×100=0.25×100=25g/100 g of solution S = \frac{5}{20} \times 100 = 0.25 \times 100 = 25 \, \text{g/100 g of solution}

Final Answer

The solubility of the solute at 30°C is 25g/100 g of solution25 \, \text{g/100 g of solution}.

This problem has been solved

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