A father is 4 times as old as his son.8 years hence, the ratio of father’s age to the son’s age will be 20:7.What is the sum of their present ages?50726865
Question
A father is 4 times as old as his son. 8 years hence, the ratio of father’s age to the son’s age will be 20:7. What is the sum of their present ages? 50726865
Solution
Let's solve this step by step:
Step 1: Let's assume the present age of the son is x years. Then the present age of the father is 4x years.
Step 2: According to the problem, 8 years from now, the ratio of the father’s age to the son’s age will be 20:7. So, we can write this as (4x + 8) / (x + 8) = 20 / 7.
Step 3: Solving this equation, we get x = 14. So, the son is 14 years old.
Step 4: The father is 4 times as old as the son, so the father is 4 * 14 = 56 years old.
Step 5: The sum of their present ages is 14 + 56 = 70.
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