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Calculate specific weight, density and specific gravity of 1 liter of liquid of weight 7N.

Question

Calculate specific weight, density and specific gravity of 1 liter of liquid of weight 7N.

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Solution

Sure, let's calculate the specific weight, density, and specific gravity of the liquid.

  1. Specific Weight: Specific weight is defined as the weight per unit volume. It is given by the formula:

    Specific Weight = Weight / Volume

Given, Weight = 7N (since weight is the force due to gravity, it is measured in Newtons) and Volume = 1 liter = 0.001 cubic meters (since 1 liter = 0.001 m^3)

So, Specific Weight = 7N / 0.001 m^3 = 7000 N/m^3

  1. Density: Density is defined as the mass per unit volume. It is given by the formula:

    Density = Mass / Volume

We know that Weight = Mass x Gravity. So, Mass = Weight / Gravity. Given that the acceleration due to gravity is approximately 9.81 m/s^2, we can calculate the mass as follows:

Mass = 7N / 9.81 m/s^2 = 0.713 kg

So, Density = 0.713 kg / 0.001 m^3 = 713 kg/m^3

  1. Specific Gravity: Specific gravity is the ratio of the density of a substance to the density of a reference substance (usually water at 4 degrees Celsius, which has a density of 1000 kg/m^3). It is given by the formula:

    Specific Gravity = Density of substance / Density of reference substance

So, Specific Gravity = 713 kg/m^3 / 1000 kg/m^3 = 0.713

Therefore, the specific weight, density, and specific gravity of the liquid are 7000 N/m^3, 713 kg/m^3, and 0.713, respectively.

This problem has been solved

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