Ka for an organic acid, HA, is 7.05 x 10–5. Calculate the value of pKb for the conjugate base. Enter your answer to 2 decimal places.

First, we need to understand that the relationship between Ka, Kb, and Kw (the ion product of water) is given by the equation Ka x Kb = Kw.

The value of Kw at 25 degrees Celsius is 1.0 x 10^-14.

Given that Ka = 7.05 x 10^-5, we can rearrange the equation to solve for Kb:

Kb = Kw / Ka

Substitute the given values:

Kb = (1.0 x 10^-14) / (7.05 x 10^-5)

Calculate the above expression to find the value of Kb.

Next, we need to find pKb. The relationship between Kb and pKb is given by the equation pKb = -log(Kb).

Substitute the value of Kb into this equation and calculate to find the value of pKb.

Remember to round your answer to 2 decimal places.