Ka for an organic acid, HA, is 7.05 x 10–5. Calculate the value of pKb for the conjugate base. Enter your answer to 2 decimal places.
Question
Ka for an organic acid, HA, is 7.05 x 10–5.
Calculate the value of pKb for the conjugate base.
Enter your answer to 2 decimal places.
Solution
First, we need to understand that the relationship between Ka, Kb, and Kw (the ion product of water) is given by the equation Ka x Kb = Kw.
The value of Kw at 25 degrees Celsius is 1.0 x 10^-14.
Given that Ka = 7.05 x 10^-5, we can rearrange the equation to solve for Kb:
Kb = Kw / Ka
Substitute the given values:
Kb = (1.0 x 10^-14) / (7.05 x 10^-5)
Calculate the above expression to find the value of Kb.
Next, we need to find pKb. The relationship between Kb and pKb is given by the equation pKb = -log(Kb).
Substitute the value of Kb into this equation and calculate to find the value of pKb.
Remember to round your answer to 2 decimal places.
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