A quadrilateral with vertices K(0,4), A(3,6), T(6,2) and E(0,-2) is a ________.

To determine the type of the quadrilateral KATE with vertices K(0,4), A(3,6), T(6,2) and E(0,-2), we need to calculate the lengths of the sides and diagonals.

1. Calculate the lengths of the sides:

   • KA = sqrt[(3-0)² + (6-4)²] = sqrt[9 + 4] = sqrt[13]
   • AT = sqrt[(6-3)² + (2-6)²] = sqrt[9 + 16] = sqrt[25] = 5
   • TE = sqrt[(0-6)² + (-2-2)²] = sqrt[36 + 16] = sqrt[52]
   • EK = sqrt[(0-0)² + (-2-4)²] = sqrt[0 + 36] = sqrt[36] = 6

2. Calculate the lengths of the diagonals:

   • KT = sqrt[(6-0)² + (2-4)²] = sqrt[36 + 4] = sqrt[40]
   • AE = sqrt[(0-3)² + (-2-6)²] = sqrt[9 + 64] = sqrt[73]

From the above calculations, we can see that the lengths of the opposite sides are not equal (KA ≠ TE and AT ≠ EK), so the quadrilateral is not a parallelogram. Also, the diagonals are not equal (KT ≠ AE), so it's not a rectangle or a rhombus.

Therefore, the quadrilateral KATE with vertices K(0,4), A(3,6), T(6,2) and E(0,-2) is a general quadrilateral.