5. An object’s mass of 9.11x10-31 kg is circling at a radius of 23.22 m. If there is a force of 3.60x10-16 N being applied, what is the object’s speed?
Question
5. An object’s mass of 9.11x10^{-31} kg is circling at a radius of 23.22 m. If there is a force of 3.60x10^{-16} N being applied, what is the object’s speed?
Solution
To solve this problem, we can use the formula for centripetal force, which is F = mv^2/r, where F is the force, m is the mass, v is the speed, and r is the radius.
We are given the values for F, m, and r, and we need to solve for v.
Rearranging the formula to solve for v gives us v = sqrt(Fr/m).
Substituting the given values into the formula gives us v = sqrt((3.60x10^-16 N * 23.22 m) / 9.11x10^-31 kg).
Performing the calculation gives us a speed of approximately 2.81x10^7 m/s.
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