What is the hybridisation of each ofthe carbon atoms present in the compoundHC C – CH = CH2
Question
What is the hybridisation of each of the carbon atoms present in the compound HC C – CH = CH2
Solution
To determine the hybridization of each carbon atom in the compound HC≡C-CH=CH2, we need to follow these steps:
Step 1: Count the number of sigma bonds (single bonds) and pi bonds (double and triple bonds) around each carbon atom.
In the given compound, we have:
- The first carbon atom (C1) is bonded to one hydrogen atom (H) and one carbon atom (C2) through a triple bond (≡).
- The second carbon atom (C2) is bonded to one carbon atom (C1) through a triple bond (≡) and one hydrogen atom (H).
- The third carbon atom (C3) is bonded to one carbon atom (C2) through a double bond (=) and one hydrogen atom (H).
- The fourth carbon atom (C4) is bonded to one carbon atom (C3) through a single bond (-) and two hydrogen atoms (H).
Step 2: Determine the hybridization of each carbon atom based on the number of sigma and pi bonds.
- For C1: It has one sigma bond and two pi bonds, so it is sp hybridized.
- For C2: It has one sigma bond and two pi bonds, so it is sp hybridized.
- For C3: It has one sigma bond and one pi bond, so it is sp2 hybridized.
- For C4: It has one sigma bond, so it is sp3 hybridized.
Therefore, the hybridization of each carbon atom in the compound HC≡C-CH=CH2 is as follows:
- C1: sp hybridized
- C2: sp hybridized
- C3: sp2 hybridized
- C4: sp3 hybridized
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