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A function h(t) increases by 1.45 over every unit interval in t and h(0)=5.Which could be a function rule for h(t)?

Question

A function h(t) increases by 1.45 over every unit interval in t and h(0)=5. Which could be a function rule for h(t)?

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Solution

To find a function rule for h(t) h(t) , we can follow these steps:

1. Break Down the Problem

  • We know that the function h(t) h(t) increases by 1.45 for every unit increase in t t .
  • We also know that h(0)=5 h(0) = 5 .

2. Relevant Concepts

  • A linear function can be expressed in the form h(t)=mt+b h(t) = mt + b , where m m is the slope and b b is the y-intercept.
  • In our case, the slope m m is 1.45, and the y-intercept b b is the initial value of the function when t=0 t = 0 .

3. Analysis and Detail

  • Since h(0)=5 h(0) = 5 , this means that when t=0 t = 0 , the function's value is 5. This gives us the conditional point to establish the y-intercept.

  • We can substitute these values into the linear function formula:

    h(t)=1.45t+5 h(t) = 1.45t + 5

4. Verify and Summarize

  • If we plug t=0 t = 0 into the function:

    h(0)=1.45(0)+5=5 h(0) = 1.45(0) + 5 = 5

  • For t=1 t = 1 :

    h(1)=1.45(1)+5=6.45 h(1) = 1.45(1) + 5 = 6.45

  • For t=2 t = 2 :

    h(2)=1.45(2)+5=7.90 h(2) = 1.45(2) + 5 = 7.90

Thus, the function rule h(t)=1.45t+5 h(t) = 1.45t + 5 effectively meets all the criteria given in the problem.

Final Answer

The function rule for h(t) h(t) is: h(t)=1.45t+5 h(t) = 1.45t + 5

This problem has been solved

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