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In a box, there are 8 orange, 7 white, and 6 blue balls. If a ball is picked up randomly, what is the probability that it is neither orange nor blue?

Question

In a box, there are 8 orange, 7 white, and 6 blue balls.

If a ball is picked up randomly, what is the probability that it is neither orange nor blue?

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Solution

To calculate the probability, we first need to know the total number of balls. We add up the orange, white, and blue balls: 8 orange + 7 white + 6 blue = 21 balls in total.

The question asks for the probability of picking a ball that is neither orange nor blue, which means we are only interested in the white balls. There are 7 white balls.

Probability is calculated as the number of desired outcomes (in this case, picking a white ball) divided by the total number of outcomes (picking any ball).

So, the probability of picking a white ball is 7 (white balls) divided by 21 (total balls), which simplifies to 1/3 or approximately 0.3333 when rounded to four decimal places.

So, the probability that the ball picked is neither orange nor blue (i.e., it's white) is 1/3 or 0.3333.

This problem has been solved

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orrect answerA bag contains 2 red, 3 green and 2 blue balls.Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

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