37) If the value of POH for weak acid equal 10 and its equilibrium constant Ka= 5.1x104, So the degree of ionization of the acid equals

To find the degree of ionization of the acid, we first need to find the concentration of the acid and the concentration of the hydronium ion.

1. The pOH is given as 10. The pH can be found using the equation pH + pOH = 14. So, pH = 14 - 10 = 4.

2. The concentration of hydronium ion [H+] can be found using the equation pH = -log[H+]. So, [H+] = 10^-pH = 10^-4 M.

3. The equilibrium constant Ka is given as 5.1x10^4. The equation for Ka is Ka = [H+][A-]/[HA]. Since the acid is weak, we can assume that [HA] is approximately equal to the initial concentration of the acid, and that [H+] is equal to [A-]. So, [HA] = Ka / [H+]^2 = 5.1x10^4 / (10^-4)^2 = 5.1x10^4 / 10^-8 = 5.1x10^12 M.

4. The degree of ionization α can be found using the equation α = [H+] / [HA] = 10^-4 / 5.1x10^12 = 1.96x10^-17.

So, the degree of ionization of the acid is approximately 1.96x10^-17.