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The measures of two adjacent angles of a parallelogram are in the ratio 3 : 2. Find the measure of each of the angles of the parallelogram.

Question

The measures of two adjacent angles of a parallelogram are in the ratio 3 : 2. Find the measure of each of the angles of the parallelogram.

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Solution

1. Break Down the Problem

We have two adjacent angles of a parallelogram that are in the ratio 3:2. Let's denote these angles as 3x3x and 2x2x. Since the sum of adjacent angles in a parallelogram is 180180^\circ, we can set up an equation to find xx.

2. Relevant Concepts

In a parallelogram, the following properties hold:

  • Adjacent angles are supplementary: Angle1+Angle2=180 \text{Angle}_1 + \text{Angle}_2 = 180^\circ
  • Given the ratio, we denote the angles as 3x3x and 2x2x.

3. Analysis and Detail

Using the supplementary property: 3x+2x=180 3x + 2x = 180^\circ Combining like terms, we get: 5x=180 5x = 180^\circ Now, solving for xx: x=1805=36 x = \frac{180^\circ}{5} = 36^\circ

Now we can find the measures of the angles:

  • First angle: 3x=3×36=108 3x = 3 \times 36^\circ = 108^\circ
  • Second angle: 2x=2×36=72 2x = 2 \times 36^\circ = 72^\circ

4. Verify and Summarize

To verify, we check if the sum of these two angles equals 180180^\circ: 108+72=180 108^\circ + 72^\circ = 180^\circ Thus, the calculations are confirmed.

Final Answer

The measures of the angles of the parallelogram are 108108^\circ and 7272^\circ.

This problem has been solved

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